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Cyrus' Math
Posted: Sat Aug 29, 2009 1:45 am
by ivanl3
“You’re standing right now with a nine delegates, from a hundred gangs and there’s over a hundred more. That’s 20,000 hardcore members, 40,000 counting affiliates and 20,000 more not organised but ready to fight. 60,000 soldiers! Now there ain’t but 20,000 police in the whole town. Can you dig it?
How does he get to the first 20K? 9 delegates * 100 gangs = 900. When he says a hundred more, I believe that means a hundred more members in each gang. Call it an even 110 members * 100 gangs = 10,000, not 20,000................I think it what he was really thinking was that each gang (al lone 100 of them) at the conclage had 110 members (even though only 9 delegates were there) and there were another 100 gangs w/ 110 members who were not invited but still in the RIF network.....THis would equate to 20k hardcore members....He did not describe iot very well though.
Re: Cyrus' Math
Posted: Sat Aug 29, 2009 2:05 pm
by The Swan
ivanl3, you're talking about Math, OK, and what about the Rules? First 10 Post in Proving Grounds...
Anyway your Topic is Funny, For Real... Never Thought about this...
Re: Cyrus' Math
Posted: Sat Aug 29, 2009 7:52 pm
by Vermin16
When he talks about there being "100 more" he means 100 more gangs. And for the first 20,000 he is talking about the total for the 100 gangs represented at the conclave. In the original opening for the movie, Cleon states that there are 120 Warriors. Given the 20,000 that Cyrus mentions for those 100 gangs, we can determine that the average gang has 200 members with some having more and some having less.
And as The Swan said, first ten posts in the proving grounds, please.
Re: Cyrus' Math
Posted: Sat Aug 29, 2009 8:43 pm
by ILLER...
all these rules are silly... no prejudice, that my hypothesis.
Re: Cyrus' Math
Posted: Wed Sep 09, 2009 8:33 pm
by wargod
ivanl3 wrote:
“You’re standing right now with a nine delegates, from a hundred gangs and there’s over a hundred more. That’s 20,000 hardcore members, 40,000 counting affiliates and 20,000 more not organised but ready to fight. 60,000 soldiers! Now there ain’t but 20,000 police in the whole town. Can you dig it?
How does he get to the first 20K? 9 delegates * 100 gangs = 900. When he says a hundred more, I believe that means a hundred more members in each gang. Call it an even 110 members * 100 gangs = 10,000, not 20,000................I think it what he was really thinking was that each gang (al lone 100 of them) at the conclage had 110 members (even though only 9 delegates were there) and there were another 100 gangs w/ 110 members who were not invited but still in the RIF network.....THis would equate to 20k hardcore members....He did not describe iot very well though.
no u are wrong he said 9 deligates from over a hundred gangs let me quote the word "over"
Re: Cyrus' Math
Posted: Wed Sep 09, 2009 8:35 pm
by wargod
ILLER... wrote:
all these rules are silly... no prejudice, that my hypothesis.
if they wasnt on here this whole forum would be in hell right now
Re: Cyrus' Math
Posted: Wed Sep 09, 2009 9:24 pm
by triscender
that is funny because i thought the same thing about his math. now it all makes sense thanks
Re: Cyrus' Math
Posted: Sat Feb 19, 2011 10:52 pm
by ivanl3
Still not following this.
9 delegates from 100 gangs (with over 100 more).....So if the 100 more means 100 more gangs and there really are 120 warriors and this is representative of the average gang that is 120*100=12,000...so a 100 more (gangs) gets you to 24K.....I guess that is it....
Re: Cyrus' Math
Posted: Sat Feb 19, 2011 11:23 pm
by 4nik8
First, let's restate the whole quote, and then let's break it down:
"You're standing right now with nine delegates from 100 gangs. And there's over a hundred more. That's 20,000 hardcore members. Forty-thousand, counting affiliates, and twenty-thousand more, not organized, but ready to fight: 60,000 soldiers! Now, there ain't but 20,000 police in the whole town. Can you dig it?"
“You're standing right now with nine delegates”
Arithmetically, It doesn’t matter how many delegates there are, just how many gangs
“…from 100 gangs. And there's over a hundred more. That's 20,000 hardcore members”
Ok, 100 gangs plus 100 more. Thus, Cyrus is likely estimating, or rounding, that there are 200 gangs. For our purposes, we'll assume major gangs average 100 members
200 gangs * 100 members each = 20,000
So there’s the aforementioned 20,000 hardcore members.
“Forty-thousand counting affiliates…”
This means that there are another 20,000 affiliates, bringing the TOTAL to 40,000
“…and twenty-thousand more, not organized, but ready to fight”
So, add to the running total another 20,000 non-affiliated criminal types, and:
20K gang members + 20K affiliates of gangs + 20K not organized = 60k = = 60,000 soldiers!
Now, there ain't but 20,000 police in the whole town. Can you dig it?"
so, can ya dig it??
Re: Cyrus' Math
Posted: Sun Feb 20, 2011 7:01 pm
by triscender
rumor has it that cyrus did teach math at the local public high school which was actually a front in order for him to recruit new gang members
Re: Cyrus' Math
Posted: Tue Mar 08, 2011 8:28 am
by The Swan
triscender wrote:rumor has it that cyrus did teach math at the local public high school which was actually a front in order for him to recruit new gang members
That's why luther killed him, he gave F to luther that monday.
Anyway there were around 100 Soldiers a Gang to me too.
Re: Cyrus' Math
Posted: Tue Mar 08, 2011 5:47 pm
by 4nik8
[quote="The Swan]That's why luther killed him, he gave F to luther that monday.[/quote]
Bob Geldof, shown here with Luther-style hair, is also perhaps most famous for not liking Mondays...
Re: Cyrus' Math
Posted: Tue Mar 08, 2011 8:58 pm
by Nuck Forbert
Luther probably failed at school because he was always wanting to go out and play.
Re: Cyrus' Math
Posted: Sun Aug 28, 2011 8:51 pm
by nightarmyWARRIOR
Who cares about math? Cyrus probably said that in a second just to know what numbers are in question. He didn't took list of all gangs on the network, grabbed a pen and a paper and start to count them all before meeting.